Refer to figures or CAP 758 Figures 2.19 and 2.20.
Given the following information, determine the Rate of Climb and the fuel required to climb:
FATO: Sea Level
Top of Climb: 4 000 ft AMSL
Temperature: ISA
Mass: 1 900 lb
Manifold Pressure for VY: 24.6 in Hg
Refer to figures.
1. Firstly, determine the Rate of Climb, using the Figure 2.19:
- Enter with the Pressure altitude of the ToC 4 000 ft from the left and move horizontally to the right to intersect the Gross mass 1 900 lb.
- Continue vertically down and read the Rate of Climb: 990 ft/min.
2. Calculate the time to climb:
- The helicopter climbs at the ToC at 4 000 ft with RoC of 990 ft/min. Thus, the time to climb is: 4 000 ft / 990 fpm = 4.04 min.
- The climb airspeed is VY: 41 kt, then the horizontal distance to climb is: 41 kt x 4.04/60 = 2.76 NM.
3. Determine the fuel flow during the climb, using the Figure 2.20:
- Enter the graph from the left with MAP 24.6 in Hg and move to the right intersecting both Sea Level and 4 000 ft lines.
- From the two intersections move vertically down to read Fuel flow at SL: 89.5 lb/hr and Fuel flow at 4 000 ft: 97 lb/hr.
- Find the average fuel flow interpolating for fuel flow at 2 000 ft: (89.5 + 97)/2 = 93.25 lb/hr.
4. Therefore, the fuel required to climb is: 93.25 lb/hr x 4.04/60 hr = 6.28 lb.
Your Notes (not visible to others)
This question has appeared on the real examination, you can find the related countries below.
-
Austro Control1
-
France1
-
Norway1
-
Spain1