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Refer to figures or CAP 758 Figures 2.19 and 2.20.
Given the following information, determine the Rate of Climb and the fuel required to climb:

FATO: Sea Level
Top of Climb: 4 000 ft AMSL
Temperature: ISA
Mass: 1 900 lb
Manifold Pressure for VY: 24.6 in Hg

  • A
    750 ft/min; 8.26 lb
  • B
    985 ft/min; 6.06 lb
  • C
    990 ft/min; 6.28 lb
  • D
    1 300 ft/min; 4.59 lb

Refer to figures.
1. Firstly, determine the Rate of Climb, using the Figure 2.19:

  • Enter with the Pressure altitude of the ToC 4 000 ft from the left and move horizontally to the right to intersect the Gross mass 1 900 lb.
  • Continue vertically down and read the Rate of Climb: 990 ft/min.

2. Calculate the time to climb:

  • The helicopter climbs at the ToC at 4 000 ft with RoC of 990 ft/min. Thus, the time to climb is: 4 000 ft / 990 fpm = 4.04 min.
  • The climb airspeed is VY: 41 kt, then the horizontal distance to climb is: 41 kt x 4.04/60 = 2.76 NM.

3. Determine the fuel flow during the climb, using the Figure 2.20:

  • Enter the graph from the left with MAP 24.6 in Hg and move to the right intersecting both Sea Level and 4 000 ft lines.
  • From the two intersections move vertically down to read Fuel flow at SL: 89.5 lb/hr and Fuel flow at 4 000 ft: 97 lb/hr.
  • Find the average fuel flow interpolating for fuel flow at 2 000 ft: (89.5 + 97)/2 = 93.25 lb/hr.

4. Therefore, the fuel required to climb is: 93.25 lb/hr x 4.04/60 hr = 6.28 lb.

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