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Refer to figure. 
What is the true average wind direction in the marked area? One wind arrow has a direction of 140°T and the other two arrows both have a direction of 090°T.

  • A

    105°T

  • B

    120°T

  • C

    085°T

  • D

    280°T

Important Note: The actual wind directions on this chart are covered up but can be just about read (or guessed) on the chart, as being FROM approximately 320°, 270° and 270°. This is how you read such winds, we always measure the direction the wind is coming from if not told otherwise. We don't know why the examiner is asking about 140°, 090° and 090° here, but we think it could be a difference of chart in the real exam (we hope it is this), or some completely wrong question that must be appealed, as such things have happened before. Nonetheless, for this one just learn to do the average calculation with the numbers given and move on I am afraid. Any further information from the real exam is highly useful, thank you.

Usually, the most accurate way to calculate average wind velocity (direction and speed) is to use a form of vector calculation which compensates for how strong each wind is and how long an aircraft expects to fly through that region for, etc. In this case though, we are asked for the (rather useless) average wind direction from 3 unknown strength winds, so it is actually much simpler.

As the directions are quite close together, simply add up all the wind directions and divide by 3.

  • 140 + 90 + 90 = 320
  • 320 / 3 = 106.7°
  • Closest answer is 105°T

Your Notes (not visible to others)



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