Refer to figures.
Given:
Take-off mass: 150 000 kg
Planned cruise at FL350
Long range MACH
Standard atmosphere (ISA)
CG: 37%
You have to cover an air distance of 2000 NM. Your flight time will be…
Refer to figures.
1. Enter the table on the first column and find the value "150" (which corresponds to 150 000 kg) and intersect with "0" (0 hundreds of kg) - read the corresponding value: 2464 NAM and 359 min.
2. From the above distance, deduct the air distance of 2000 NM we must cover = 2464 NM - 2000 NM = 464 NM.
4. On the table, find the timing corresponding to 464 NM.
- There is no distance corresponding to 464 NM - therefore, we must interpolate between 451 NM - 70 min and 472 NM - 73 min => we get roughly 72 min for 464 NM.
5. Find the time necessary to fly 2000 NM.
- It will be the difference between 359 min and 72 min = 287 min
6. Apply the "Climb Correction"
- For FL350 => a correction of 6 min must be added.
287 min + 6 min = 293 min
7. Apply the "Descent Correction"
- "Long Range Cruise" and FL350 => we must apply a correction of 10 min
293 min + 10 min = 303 min
Your Notes (not visible to others)
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