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A flight is planned over a distance of 360 NM. The TAS is 210 kt, the heading is 090° T, and the wind velocity is 090°/30 kt.

What is the distance to the Point of Equal Time PET and how long will it take to get there?

  • A
    206 NM and 69 minutes.
  • B
    180 NM and 45 minutes.
  • C
    154 NM and 51 minutes.
  • D
    210 NM and 70 minutes.

Refer to figure.
Solving from Heading (HDG) & Ground Speed (GS), knowing WV, TAS and required track.

1. Set wind direction to 090º under the "TRUE HEADING" index at the top.
2. Set the center point on the True Airspeed (TAS) of 210 kt.
3. Mark the wind velocity 30 kt down from the centre point.
4. Initially, set the True Track under the "TRUE HEADING" index.

  • GS home: 270º
5. The groundspeed for this track is approximately 240 kt.
  • GS out: 090º

5. The groundspeed for this track is approximately 180 kt.

We can now apply the formulas:
Distance to PET = (GS home x Distance) / (GS out + GS home)
Distance to PET = (240 x 360) / (180 + 240)
Distance to PET = 206 NM

Time to PET = Distance to PET / GS out
Time to PET = 206 NM / 180 kt = 1.144 hrs (x60 to get minutes) = 68.67 min = approx. 69 min

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