(Assume g = 10 m/s

^{2})

The formula to work out radius of turn is;

**Radius = (TAS) ^{2} / (g x tan(bank angle))**

Where g = the acceleration due to gravity, usually 9.81 m/s^{2}, but assumed to be **10 m/s ^{2}** in some questions, like this one.

__All units are in metric__. Radius (m), TAS (m/s), g (m/s

^{2}).

First lets convert 120 kt into metres per second. 120 kt is 120 nautical miles per 1 hour, so multiple by the amount of metres in a nautical mile [1852] (now you have metres per hour). Then divide by the amount of seconds in an hour [3600]. Now you have metres per second.

TAS = 120 kt x 1852 / 3600 = **61.73 m/s**

Substituting the known figures into the radius formula above, we get;

Radius (m) = (61.73)^{2} / (10 x tan(60º)) = **220 m**

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