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Given:

Distance from departure to destination: 1100 NM
True track: 280°
W/V: 100/80
TAS: 440 kt

What is the distance and time of the PET from the departure point?

  • A
    Distance: 550 NM Time: 75 min
  • B
    Distance: 650 NM Time: 108 min
  • C
    Distance: 450 NM Time: 52 min
  • D
    Distance: 650 NM Time: 75 min

Wind is completely tail wind in the way out and headwind in way home
GS Out: 520 kts
GS Home: 360 kts

Distance to PET = (GS home x Distance) / (GS out + GS home)
Distance to PET = ( 360 x 1100) / (520 + 360) = 450 NM

Time to PET = Distance to PET / GS out
Time to PET = 450 / 520 = 0.86 hr = 52 minutes

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