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The helicopter’s floor loading limit is given as 4 000 N/m2. What is the maximum permissible mass for a box 0.5 m x 0.5 m, under 1 G conditions? (Assume G = 10 m/sec2).

• A
100 kg
• B
105 kg
• C
98 kg
• D
104 kg

A cabin floor or cargo hold has set limitations by the Manufacturer which must be observed by the Operators. There are two types of loads to be considered:

1. Distribution Load Intensity
2. Floor Running Load

The distribution load intensity is the more commonly used limitation given as “maximum static mass per unit area the floor is designed to continuously carry”. In this case any unit of mass can be combined with any unit of area, provided the floor loading limitations are within limits. Distribution load intensity is measured as kg/m2 or lbs/ft2.

The floor running load can be calculated by the mass divided by the length of the load along the fore and aft axis of the rotorcraft. This load is measured in kg/in.

First find out the area of the load:

• Area = 0.5 m x 0.5 m = 0.25 m2

Thereafter find out the load for the area based on the floor loading limit:

• Load = 0.25m2 x 4 000 N/m2 = 1 000 N

Knowing the force convert it into Mass in kg.:

• Mass = Force / G
• Mass = 1 000 N / 10 m/s2 = 100 kg

NOTE:

The newton is the unit of force in the International System of Units. It is defined as kgm/s².

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