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Refer to figure.
The pilot of a light twin-engined aircraft has filled in the flight log correctly for a charter flight to Nice in France. What is the actual ground speed at TORDU? If the groundspeed at TORDU remains the same, what will be the ATO at RODRA?
  • A
    GS TORDU: 171 kt
    ATO RODRA: 07:11
  • B
    GS TORDU: 167 kt
    ATO RODRA: 07:17
  • C
    GS TORDU: 185 kt
    ATO RODRA: 07:11
  • D
    GS TORDU: 185 kt
    ATO RODRA: 07:09

Refer to figure.
The aircraft covered the flight leg from SOPET to TORDU in: 06:46 - 06:34 = 12 min.
So, its Actual Groundspeed will be: Leg distance / Leg time = (37 NM / 12 min) x 60 = 185 kt.

Distance from TORDU to RODRA: 26 + 14 + 14 + 17 = 71 NM

The question states that the groundspeed at TORDU remains unchanged for the remainder of the flight. We know the distance TORDU - RODRA and the GS. Therefore, we can calculate the flight time TORDU - RODRA: (71 NM ÷ 185 kt) x 60 = 23 min.

The actual time overhead TORDU was 06:46. The aircraft will reach RODRA 23 min later at: 07:09.

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