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An aeronautical chart has a published scale of 1 inch = 15 NM. An aircraft is flying on a true heading of 089° with a groundspeed of 150 kt. Calculate the chart distance covered by the aircraft in 25 minutes.
  • A
    7,7 cm
  • B
    4,2 cm
  • C
    5,7 cm
  • D
    10,6 cm

A scale of 1 inch=15 NM means that "each inch on the chart equals to 15 NM on the ground".

The given heading 089o is NOT required for this question.

The ground distance covered is given by the formula:
Ground distance(NM) = Ground Speed(kt) x Time(hr) = 150 kt x 25/60 hr = 62.5 NM

It is known that 1 inch = 15 NM, so 62.5 NM = 4.17 inches.

It is known that1inch = 2.54 cm, thus 4.17 inches = 10.6 cm.

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