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On a VFR flight, the traffic circuit altitude has to be established 5 NM before reaching the destination aerodrome. The descent must begin no later than how many nautical miles’ ground distance from the airfield?

Rate of descent: 500 ft/min
Ground speed during descent: 130 kt
Initial altitude: 4500 ft AMSL
Traffic circuit altitude: 2500 ft AMSL

  • A
    20 NM
  • B
    14 NM
  • C
    25 NM
  • D
    9 NM

4500-2500= 2000 ft at 500 ft/min

2000/500= 4 mins for descend

Distance = Speed * Time => 130 * 4/60 = 8.66 NM

8.66 + 5 = 13.66 NM

The closest answer is 14 NM.

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