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You refuel with 220 IMP Gallons. What is the mass in Kg with an specific gravity of 0.82?
  • A
    840 kg
  • B
    220 kg
  • C
    224 kg
  • D
    820 kg

Refer to figure.

There are two methods of solving this question:
(1) Converting IMP into litres and litres into kilograms:
Imperial Gallons to Litres (l) => Litres = Imp. Gal × 4.546

  • 220 IMP x 4.546 = 1000.12 litres
Conversion between Fuel volume and mass: Fuel volume in litres x Specific Gravity (density) = Fuel Mass in Kg
  • 1000.12 litres x 0.82 = 820 kg

(2) Use CRP5/Flight computer:
Align 220 IMP Gallong - using the INNER ring.
Look for the "KGS" scale, use the Specific Gravity of 0.82 on the outer ring and read 820 kg on the inner ring.

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