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Determine the distance which will be shown on a DME display when the aircraft is at FL 240 and 4 NM plan range from the DME station:

For the calculation use the following assumptions/approximations:
QNH is 1013 hPa
Pressure altitude is true altitude.
Result to the nearest whole nautical mile.
  • A
    3 NM
  • B
    4 NM
  • C
    6 NM
  • D
    8 NM

Refer to figure.

The question states that we can regard Pressure Altitude to be the True Altitude. Therefore, True Altitude equals 24 000 ft.

  • 24 000 ft / 6 076 = 4 NM (approx.)

Using the Pythagoras theorem:

X2 = 42 + 42
X2 = 32
X = √32 = 5.65 NM

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